X-Git-Url: https://git.opendaylight.org/gerrit/gitweb?p=controller.git;a=blobdiff_plain;f=opendaylight%2Fsal%2Fapi%2Fsrc%2Fmain%2Fjava%2Forg%2Fopendaylight%2Fcontroller%2Fsal%2Fcore%2FPath.java;h=5f2dc92aee8c06dd8e204a10af04910cf426bafb;hp=5584cd9461abc54d3e79a5c57737f576c0b9e816;hb=2699e9c1550b01d72fea94cc24bb89837edc0d76;hpb=42210c03b0a4c54706320ba9f55794c0abd4d201

diff --git a/opendaylight/sal/api/src/main/java/org/opendaylight/controller/sal/core/Path.java b/opendaylight/sal/api/src/main/java/org/opendaylight/controller/sal/core/Path.java
index 5584cd9461..5f2dc92aee 100644
--- a/opendaylight/sal/api/src/main/java/org/opendaylight/controller/sal/core/Path.java
+++ b/opendaylight/sal/api/src/main/java/org/opendaylight/controller/sal/core/Path.java
@@ -11,7 +11,7 @@
  * @file   Path.java
  *
  * @brief  Describe a path as a sequence of Edge such that from
- * each of its Tail Node there is an link to the next Head Node in the sequence
+ * each of its Head Node there is an link to the next Tail Node in the sequence
  *
  */
 package org.opendaylight.controller.sal.core;
@@ -29,7 +29,7 @@ import javax.xml.bind.annotation.XmlElement;
 
 /**
  * Describe a path as a sequence of Edge such that from
- * each of its Tail Node there is an link to the next Head Node in the
+ * each of its Head Node there is an link to the next Tail Node in the
  * sequence
  *
  */
@@ -50,15 +50,15 @@ public class Path implements Serializable {
     /**
      * Construct an object representing a path, the constructor will
      * check if the passed list of edges is such that for every
-     * consecutive edges the tailnode of the first edge coincide with
-     * the head node of the subsequent in order for connectivity to be there.
+     * consecutive edges the head node of the first edge coincide with
+     * the tail node of the subsequent in order for connectivity to be there.
      *
      * @param edges Edges of the path
      *
      */
     public Path(List<Edge> edges) throws ConstructionException {
-        // Lets check if the list of edges is such that the tail node
-        // of an edge is also the head node of the subsequent one
+        // Lets check if the list of edges is such that the head node
+        // of an edge is also the tail node of the subsequent one
         boolean sequential = true;
         if (edges.size() >= 2) {
             for (int i = 0; i < edges.size() - 1; i++) {